Flight times for commuter planes are normally distributed, with a mean time of 94 minutes and a standard deviation of 7 minutes. using the empirical rule, approximately what percent of flight times are between 80 and 108 minutes?

The percent of flight times is 95%

Step-by-step explanation:

* Lets revise the empirical rule

- The Empirical Rule states that almost all data lies within 3

 standard deviations of the mean for a normal distribution.  

- The empirical rule shows that

# 68% falls within the first standard deviation (µ ± σ)

# 95% within the first two standard deviations (µ ± 2σ)

# 99.7% within the first three standard deviations (µ ± 3σ).

* Lets solve the problem

- Flight times for commuter planes are normally distributed, with a

 mean time of 94 minutes

∴ μ = 94

- The standard deviation is 7 minutes

∴ σ = 7

- One standard deviation (µ ± σ):

∵ (94 - 7) = 84

∵ (94 + 7) = 101

- Two standard deviations (µ ± 2σ):

∵ (94 - 2×7) = (94 - 14) = 80

∵ (94 + 2×7) = (94 + 14) = 108

- Three standard deviations (µ ± 3σ):  

∵ (94 - 3×7) = (94 - 21) = 73

∵ (94 + 3×7) = (94 + 21) = 115

∵ The percent of flight times are between 80 and 108 minutes

∴ The empirical rule shows that 95% of the distribution lies  

  within two standard deviation in this case, from 80 to 108  minutes

* The percent of flight times is 95%

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step-by-step explanation:

a rotation about point l

step-by-step explanation:

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