Suppose a random sample of 64 men has a mean foot length of 27.5 cm with a deviation of 2 cm. construct a 95% confidence interval for the mean of the population.

The 95% on the z-table is 1.96.

Now find the standard error of the mean by dividing standard deviation by the square root of the sample:

2 / √64 = 0.25

Multiply the standard error by the z-table :

0.25 x 1.96 = 0.49

Now add and subtract that from the mean:

27.5 - 0.49 = 27.01 = 27

27.5 +0.49 = 27.99 = 28

The answer is: 27 ≤ u ≤ 28

i'm not entirely sure

step-by-step explanation:

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