Asingle die is rolled twice. the set of 36 equally likely outcomes is {(13),nbsp (56)}. find the probability of getting two numbers whose sum is < 13.

1

Step-by-step explanation:

Given : A single die is rolled twice.

The set of 36 equally likely outcomes is {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3), (5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

The maximum sum of the of two numbers appear on two dices is 12.

So the event that of getting two numbers whose sum is < 13 is certain and the probability of certain event is 1.

Thus,  the probability of getting two numbers whose sum is < 13 =1

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the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844