Let the universal set, s, have 203 elements. a and b are subsets of s. set a contains 98 elements and set b contains 81 elements. if the total number of elements in either a or b is 173, how many elements are in a but not in b?

There are 92 elements in A but not in B.

Step-by-step explanation:

Since we have given that

n(S) = 203

n(A) = 98

n(B) = 81

n(A∪ B) = 173

We first find the value of n(A∩B).

We need to find the number of elements that are in A but not in B.

Hence, there are 92 elements in A but not in B.

92

Step-by-step explanation:

it is given that total number of elements =203

set A contains 98 that is A=98

set B contain 81 elements B=81

It is given that either A or B is 173

we know the formula

173=98+81 -  

 =  6

so the elements in A but not B =98-6=92

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

it is true

step-by-step explanation:

all the combinations add up i used   calculator