Find the area of the shaded regions below. give your answer as a completely simplified exact value in terms of π (no approximations).
plss solve both

Part 1) The area of the shaded region is

Part 2) The area of the shaded region is

Step-by-step explanation:

Part 1) Figure N 1

I assume that the figure ABCD is a square

we know that

The area of the shaded region is equal to the area of the square ABCD minus the area of semicircle BC plus the area of semicircle AD

therefore

The area of the shaded region is equal to the area of the square ABCD

The area of the square is

Part 2) Figure N 2

I assume that the triangle ABC is a right isosceles triangle

so

AB=BC

AB ⊥ BC

The area of the shaded region is equal to the area of triangle plus the area of semicircle

A) Find the area of the triangle ABC

The area of triangle is

substitute

B) Find the area of semicircle

The area of semicircle is equal to

we have

-----> the radius is half the diameter

substitute

therefore

The area of the figure is equal to

question:

could we have options?

idk

step-by-step explanation:

i don't know