Square efgh stretches vertically by a factor of 2.5 to create rectangle e'f'g'h'. the square stretches with respect to the x-axis. if point h is located at (-2.0), what are the coordinates of h'?

The coordinates of H' are (-2 , 0)

Step-by-step explanation:

* Lets explain how to solve the problem

- A vertical stretching is the stretching of the graph away from

 the x-axis

- If k > 1, the graph of y = k•f(x) is the graph of f(x) vertically stretched

 by multiplying each of its y-coordinates by k.

- A vertical compression is the squeezing of the graph toward

 the x-axis.

- If 0 < k < 1 (a fraction), the graph of y = k•f(x) is f(x) vertically

 compressed by multiplying each of its y-coordinates by k.

- In the problem

∵ Square EFGH stretches vertically by a factor of 2.5

∵ Its image is the rectangle E'F'G'H'

∵The square stretches with respect to the x-axis

∴ The y-coordinates of all the point of the square will multiply by

   the factor of the stretching

∵ The factor of the stretching is 2.5

∵ The coordinates of point H are (-2 , 0)

∴ H' = (-2 , 0 × 2.5) = (-2 , 0)

∴ The coordinates of H' are (-2 , 0)

4400

step-by-step explanation:

the answer to the expression is 83