Rewrite the given quadratic function in the form f(x) = a(x - h)2 + k. then, enter the x-coordinate of the minimum point of the function:
f(x)=4x^2-12x-15

The minimum occurs at .

Step-by-step explanation:

The in is the same in where:

and .

So let's find .

.

To find , we must use the expression that is and evaluate it for , like so:

So the vertex form is .

-----------------Another way----------------------------

You could just complete the square.

I like to use the following to help me formulate the process:

.

Let's start. My formula requires coefficient of to be 1 so factor out the 4 from the first two terms:

Now we are going to add the to complete the square; whatever you add in you must also subtract out.

-----------------So anyways either way you choose....-----------------------

The minimum or maximum will occur at the vertex. Since is positive the parabola is open up and therefore does have a minimum.

tells us the vertex is .

So h is the x-coordinate of the vertex.

So the minimum occurs at .

step-by-step explanation:

but which class are u may know that first