Mathematics, 08.08.2019 01:30 UnusualKc8513
suppose that y(1)=4 and y? (1)=3. if h(x)=(y(x))^3, then the chain rule tells us that h'(1)=3(y(1))^2y'(1). therefore, h'(1)=
for the same function y as described above, if k(x)=2(y(x))^4, then k'(1)=
how to get this answer?
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suppose that y(1)=4 and y? (1)=3. if h(x)=(y(x))^3, then the chain rule tells us that h'(1)=3(y(1))^...
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