Find a polynomial function of lowest degree with real coefficients having zeroes of 2 and -si (show all work to earn credit.)

 The required polynomial of lowest degree is

Step-by-step explanation:  We are given to find a polynomial function of lowest degree with real coefficients having zeroes of 2 and -5i.

We know that

if x = a is a zero of a real polynomial function p(x), then (x - a) is a factor of the polynomial p(x).

So, according to the given information, (x - 2) and ( x + 5i) are the factors of the given polynomial.

Also, we know that complex zeroes occur in conjugate pairs, so 5i will also be a zero of the given polynomial.

This implies that (x - 5i) is also a factor of the given polynomial.

Therefore, the polynomial of lowest degree (three) with real coefficients having zeroes of 2 and -5i is given by

Thus, the required polynomial of lowest degree is

x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3

what is the question here

step-by-step explanation: