You select a family with three children. it m represents a male child, and f represents a female child, the set of equally likely outcomes for the children's genders is (mmm, mimf mfm, mff, fmm, fmf, ffm, fff ) find the probability of selecting a family with fewer than 5 male children p(fewer than 5 male children) type an integer or a simplified fraction.)

Answer with explanation:

→If a Family has five children, then Total likely outcome can be represented as:

Five Male =1

Five Female =1

4 Male +1 Female =4

4 Female +1 Male =4

3 Male +2 Female =10

3 Female +2 Male =10

Total Possible Outcome

 =1+1+4+4+10+10

or

   =2×2×2×2×2

     =32

,i.e either a children can be a male or female.

→If all the five childrens are male , then in the family number of children fewer than 5 male children =32-1=31

→Probability of an Event

→→Probability of selecting a family with fewer than 5 male children

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5