The paired data below consist of the temperatures on randomly chosen days and the amount a certain kind of plant grew (in millimeters): temp 62 76 50 51 71 46 51 44 79 growth 36 39 50 13 33 33 17 6 16 find the value of the linear correlation coefficient r.

Step-by-step explanation:

Given is a paired data which consist of temperatures (X in mm) and growth

We have to find the linear correlation i.e. the measure of association between these two variables.

xyxyx^2y^2

6236223238441296

7639296457761521

5050250025002500

51136632601169

7133234350411089

4633151821161089

51178672601289

446264193636

791612646241256

Mean58.88888889271623.8888893628.444444916.1111111

cov33.88888889    

std dev x13.4391633314.50861813    

sx *sy      

r0.195529176    

Hence we find that correlation coefficient 0.1955.

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !