The article “gas cooking, kitchen ventilation, and exposure to combustion products” reported that for a sample of 50 kitchens withgas cooking appliances monitored during a one-week period, the sample mean co2level(ppm) was 654.16, and the sample standard deviation was 164.43.(a) calculate and interpret a 95% confidence interval for true average co2level in thepopulation of all homes from which the sample was selected.(b) suppose the investigators had made a rough guess of 175 for the value ofsbeforecollecting data. what sample size would be necessary to obtain an interval widthof 50 ppm for a confidence level of 95%?

answer: idk

step-by-step explanation:

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)