Acompany produces steel rods. the lengths of the steel rods are normally distributed with a mean of 208.6-cm and a standard deviation of 0.6-cm. for shipment, 12 steel rods are bundled together. find the probability that the mean length of a randomly selected bundle of steel rods is greater than 208.2-cm.

0.9896

Step-by-step explanation:

Given : A company produces steel rods. The lengths of the steel rods are normally distributed with

Mean :

Standard deviation :

Sample size : = 12

Let x be the random variable that represents the lengths of the steel rods .

To find probability , first we find z-score

Z-score :

For x= 208.2-cm.

By using standard normal distribution table , the probability that the mean length of a randomly selected bundle of steel rods is greater than 208.2-cm :-

Hence, the required probability is 0.9896.

-1, -2, -3, -4, -6

step-by-step explanation:

12

step-by-step explanation:

12 + 5 = 17

12x2=24

24-7=17