Assume that a simple random sample has been selected and test the given claim. use the p-value method for testing hypotheses. identify the null and alternative hypotheses, test statistic, p-value, and state the final conclusion that addresses the original claim. the ages of actresses when they won an acting award is summarized by the statistics nequals79, xequals35.9 years, and sequals11.1 years. use a 0.01 significance level to test the claim that the mean age of actresses when they win an acting award is 32 years.

alpha = 0.05

xbar = 42.5

s = 5.9

n = 15

df = n-1 = 15 - 1 = 14

we will use the t distribution because n > 30 is not true and we don't know sigma.

hypothesis:

h0: mu = 32.6

h1: mu =/= 32.6

claim is in the null hypothesis h0. this is a two tailed test. the null will be rejected if the test statistic is not between the critical values.

t = (42.5 - 32.6)/(5.9/sqrt(15))

t = 6.49873476736499

t = 6.4987

critical values (alpha = 0.05, df = 14)

the test statistic 6.4987 is not between the critical values -2.145 and 2.145. so we reject the null hypothesis. there is enough statistically significant evidence to reject the null.

this means that the population mean mu is not 32.6. the initial claim is false.

the answer for your question is

step-by-step explanation:

it would be 4 over -2 divided by -1 over 3.

if you want a solution it would be 4

you flip it so it would be 4/-2 divided by 3/-1 then it would be 12/3 and you would simplify it to 4