If the length of one leg of a right triangle is 8 and the hypotenuse is √113, what is the length of the other leg?

To answer this question you must use Pythagorean theorem

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 8

b = unknown

c = √113

^^^Plug these numbers into the theorem

Simplify

64 + b² = 113

solve for x

= 49

Take the square root of both sides to cancel out the square from the b:

√b² = √49

b = 7

Hope this helped!

~Just a girl in love with Shawn Mendes

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

4

step-by-step explanation: