Trying to group factor an equation, n^2-3b^2+nb-3n
can anyone me understand?
you!

n(n - 3) + b(n - 3b)

Step-by-step explanation:

n^2 - 3b^2 + nb - 3n =

Rearrange the terms in a way in which you have two terms with a common factor and another two terms with a common factor.

= n^2 - 3n + nb - 3b^2

Now factor a common factor out of each two terms.

= n(n - 3) + b(n - 3b)

the answer is about 24 dollars