Mathematics, 12.08.2019 20:10 Chandler1Gaming
Use your graphing calculator to solve the equation graphically for all real solutions x^3−4x^2−2x+12 = 0, x^3-4x^2-2x+12=0.
Answers: 1
, ![x_2=1-\sqrt{7}\approx -1.65[tex] and [tex]x_3=1+\sqrt{7}\approx 3.65](/tpl/images/0174/4290/39db1.png)
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is one real root of the equation. For the other two we use the general formula for second degree equations:
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and 
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Use your graphing calculator to solve the equation graphically for all real solutions x^3−4x^2−2x+12...
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