You are given a list of students names and their test scores. design a pseudocode that does the following: (a) calculates the average test scores.(b) determines and prints the names of all the students whose test scores are below the average test score.(c) determines the highest test score.(d) prints the names of all

List_of_students = {};    //Structure array that contains the scores of students and Names

Number_of_students = size(List_of_students);

Average_score ;   //Variable Stores average score

Below_Average = [];   //That is initially filled with zeros  

Highest_score ; //Initialize variable to store highest score

for ( i = 0 ; i < Number_of_students; i = i + 1)

{

      Average_score  = Average_score + List_of_students(i);    

     if ( i = 15)

      {

        Average_score  = Average_score / Number_of_students;

      }

}

for ( j = 0; j < Number_of_students ; i = i + 1)

{

    if (   List_of_students(j)  < Average_score)

     {

         print( "student  %name got %score , List_of_students(j),          List_of_students(j) )

     }

}

Compare_Score = 0;   //Variable to compare score

for ( k = 0; K < Number_of_students; k = k+1)

{

     if ( List_of_students(k) => Compare_Score)

    {

        Compare_Score = List_of_students(k);

    }

}

Highest_Score = Compare_Score;

Step-by-step explanation:

my guess is

step-by-step explanation:

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).