the function f(x) = 4(2)x represents the growth of a butterfly population every year in a remote swamp. jan wants to manipulate the formula to an equivalent form that calculates five times a year, not just once a year. which function is correct for jan's purpose, and what is the new growth rate?
f(x) = 4(1.15)x; growth rate is 5%
f(x) = 4(1.15)5x; growth rate is 15%
f(x) = 4(2)x; growth rate is 200%
f(x) = 4(2)x, growth rate is 5%

  f(x) = 4(1.15)^(5x); growth rate is 15%

Step-by-step explanation:

If x still represents the number of years, but we want to see a growth factor that corresponds to 1/5 of a year, we can write the formula as ...

The growth factor is 1+r = 1.15, so r = 0.15 = 15%, the growth rate in a 1/5-year interval.

_____

Comment on the question and answer

If Jan wants to compute the growth in 1/5-year intervals, it isn't clear why the desired formula uses an exponent of 5x, signifying that x is measured in years. We would expect the independent variable to be the number of 1/5-year intervals, rather than 1/5 that number.

f(x) = 4(1.15)^(5x); growth rate is 15%

Step-by-step explanation:

The function f(x) = 4(2)x represents the growth of a butterfly population every year in a remote swamp. Jan wants to manipulate the formula to an equivalent form that calculates five times a year, not just once a year. The function that is correct for Jan's purpose is f(x) = 4(1.15)^(5x) and the new growth rate is 15%.

1+r = 1.15

Therefore, the growth rate is 15%

66.666666667%

step-by-step explanation:

divide 150 by 100

divide 100 by 1.5

there you go!

decreased by 33.333333334%

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true