It is claimed that the expected length of time some computer part may work before requiring a reboot is 26 days. in order to examine this claim 80 identical parts are set to work. assume that the distribution of the length of time the part can work (in days) is exponential. the central region that contains 70% of the distribution of the average is of the form e(x) ± c, where e(x) is the expectation of the sample average. the value of c is (you are asked to apply the normal approximation to the distribution of the average of the 80 parts that are examined. the answer may be rounded up to 3 decimal places of the actual value.)

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

the answer is  

a.

4,624π mm2

step-by-step explanation:

1) letter c.

2) 4 square root of 9

hope this

step-by-step explanation: