If g(x)=5x-3 and h(x)= sqaure root of x find (g o h)(4)

The answer is 7

Step-by-step explanation:

We have:

if g(x)=5x-3 and h(x)= sqaure root of x.

We have to find (g o h)(4).

(g o h) = g(h(x))

Plug the value of h(x) which is √x in g(x)

g(h(x))= g(√x)

Now plug the value √x in g(x).

g(h(x))= g(√x) = 5√x-3

Now to find (g o h)(4) plug in 4 in place of x

(g o h)(x)=g(h(x))= g(√x) = 5√x-3

(g o h)(4)= g(h(4)) = g(√4) = 5√4-3

Therefore:

(g o h)(4) = 5(2)-3

(g o h)(4) = 10-3 = 7

Thus the answer is 7

Step-by-step explanation:

Given the function g(x):

And the function h(x):

We need to plug the function   into the function  , in order to find . Then:

Now, in order to find  , we need to substitute into . Then, this is:

x + 4/7

step-by-step explanation:

use cymath

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.