Idon’t understand how to do question c for the first problem, and for the second question what is a gradient and how do i find it? i need to show work, can someone me

1a. Use the Pythagoren theorem:

AC^2 = 7.2^2 + 9.6^2 ==> AC = 12

1b. Same as in (1a), but now use AC as the length of another leg, and AG would be the hypotenuse in triangle ACG:

AG^2 = AC^2 + 3.5^2 ==> AG = 12.5

1c. This requires some trigonometry. In the triangle ACG, we have two legs of length AC = 12 and CG = AE = 3.5. Then the angle made by AG with the floor, which is the same as the angle made by AG and AC, is such that

2a. (6, -5) is not on the line because

2b. Gradient is another word for slope. Here we can rewrite the line as

which tells us the slope is -2/3.

2c(i). Any line perpendicular to L has a slope equal to the negative reciprocal of the slope of L. Here, that would be 3/2.

2c(ii). Using the point-slope formula, this perpendicular line has equation

the least common denominator is 40

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.