The graph of which of the following inequalities has open circles on -8 and 2 with a line segment between them?

|x + 3| < -5
|x + 8| < 2
|x + 3| < 5

Open circles means not including them,and with aline between them,
baseically it means
from -8 to 2, not including -8 or 2 or
-8<x<2 is the solution

one way to solve is to eliminate, then subsitute

look at first one
remember that|._.|>0
so this is impossible that |anything|<-5

cross out first choice

2nd one
let's input a point from the solutions set

if we input 0 for x in the other 2 equations we get (-8<x<2 is solution set and 0 is in there)

|0+8|<2, 8<2 false

|0+3|<5
3<5
treu

answer is third one

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