What is the volume of a box that can be created from a sheet of metal that measures 12 inches by 30 inches assume there is no top to the box

Step-by-step explanation:

Given that metal sheet is available with dimensions 12x30 inches.

Let x be the side of the square cut from all the four sides so that they can be folded to make open box.

The dimensions of the box would be 12-2x, 30-2x and x

Volume = V(x) =

x can take only values upto 6 since at 6 the length =0

Let x =5

Then volume = 5(20)(2) =200 square inches.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

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step-by-step explanation:

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