The second side of a triangular deck is 3 feet longer than the shortest side, and the third side is 3 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 72 feet, what are the lengths of the three sides?

The length of the shortest side is 18 ft

The length of the second side is 21 ft

The length of the third side is 33 ft

Step-by-step explanation:

Let

x > the length of the shortest side

y > the length of the second side

z > the length of the third side

we know that

The perimeter of the deck is

P=x+y+z

P=72 ft

so

72=x+y+z > equation A

y=x+3 > equation B

z=2x-3 > equation C

substitute equation B and equation C in equation A and solve for x

72=x+(x+3)+(2x-3)

72=4x

x=72/4

x=18 ft

Find the value of y

y=18+3=21 ft

Find the value of z

z=2(18)-3=33 ft

therefore

The length of the shortest side is 18 ft

The length of the second side is 21 ft

The length of the third side is 33 ft

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i am not sure :

step-by-step explanation: