How does the graph of y = 3x compare to the graph of y = 3–x?

In this problem, we have two functions. Let's call the first functions as:

and the second function:

So we can compare this functions as follows:

Both graphs represent the equation of a line

Step-by-step explanation:

Both graphs represent the equation of a straight line with the equation:

y = mx + c

Where m = the slope of the line and

c = intercept

Comparing both equations to the equation of a line given above:

In the first equation y = 3x

The slope, m = 3 (Positive slope)and

Intercept, c = 0

In the equation y = 3 -x

the slope, m = -1 (negative slope)

Intercept, c = 3

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco