Two spheres have volumes of 8r cm3 and 64st cm3. if the surface area of the smaller sphere is 16 t cmwhat is thesurface area of the larger sphere? o 641 cm2o 96t cm128 cm2561t cm

Well

V=(4/3)pir^2
SA=4pir^2

we don't need the SA of smaller sphere wh cares

larger sphere, solve for pir

larger sphereV=64pi
V=(4/3)pir^3
64pi=(4/3)pir^3
multiply both sides by 3/4 to clea fraction
48pi=pir^3
divide both sides by pi
48=r^3
cube root both sides
2∛6=r

sub back

SA=4pir^2
r=2∛6
SA=4pi2∛6^2
SA=4pi4∛36
SA=16∛36pi
aprox
52.83pi

SA=52.83pi cm^2
what is wrong with the computer systems? the answer is never listed and why do they have to give you the surface area of the smaller one

I hope the answer is not "oh, 8pi times 2=16pi, so 64pi times 2=128pi"

answer is not listed
I don't know what's happening to the math system