Alocal juice manufacturer distributes juice in bottles labeled 12 ounces. a government agency thinks that the company is cheating its customers. the agency selects 20 of these bottles, measures their contents, and obtains a sample mean of 11.7 ounces with a standard deviation of 0.7 ounce. use a 0.01 significance level to test the agencyʹs claim that the company is cheating its customers. round the test statistic to the nearest thousandth.

Let be the population mean .

By considering the given information , we have the following hypothesis :-

Since the alternative hypotheses is two tailed so the test is a two tailed test.

We assume that the quantity of juices is normally distributed.

Given : Sample size :  n=20 , which is less than 30 .

It means the sample is small so we use t-test.

Sample mean :

Standard deviation :

Test statistic for population mean :-

Critical value :

Since the  critical value is greater than the observed value , so we reject the null hypothesis.

Hence, we have enough evidence to support the agency's claim.

she would want to sell 10 full-year subscriptions and at least 9 half-year subscriptions to get a total of at least $300. 

i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

mark brainliest!

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497