The normal temperature range for yuma, az on january 11 is at least 48 degrees but no higher than 64 degrees fahrenheit. which interval describes the normal temperature in yuma, az on january 11?

Our required interval for temperature is

Step-by-step explanation:

Since we have given that

The normal temperature range for Yuma, on Janurary is atleast = 48 degrees

and the highest temperature on that day is no higher than 64 degrees.

Let the temperature in Yuma be 'x'.

So, we know that for atleast means it can 48 degrees or more, and no higher than means it should be equa to or less than 64 degrees.

Mathematically, it is expressed as

Hence, our required interval for temperature is

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

the answer is 3/2 and for decimal: 1.5

hope i

-lavira: )