Find the critical points of dy/dx=15-2y-y^2 and determine if they are stable, unstable or semi-stable.

3...stable critical value, -5 unstable critical vale

Step-by-step explanation:

A critical value of the given differential is a value such that the left hand side of the equation is equal to zero, i.e, y such that

By the last equation the critical values of the given differential equation are y=-5, 3.

Now, since

It holdst that

and

hence 3 is a stable critical value.

Also note that

and

hence -5 is an unstable critical value.

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !

answerim :

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step-by-step explanation:

im not sure but my dad knows