What is the vertex of g(x) = 3x2 − 12x + 7?
a) (−6, −5)
b) (−2, −5)
c) (2, −5)
d) (6, −5)

C)   (2, -5).

Step-by-step explanation:

Convert to vertex form:

3x^2 - 12x + 7

= 3(x^2 - 4x) + 7

Completing the square:

= 3[ (x - 2)^2 - 4)] + 7

= 3(x - 2)^2 - 12 + 7

= 3(x - 2)^2 - 5.

Comparing with the general form

a(x - b)^2 + c  we see that the vertex is (b, c)  =   (2, -5).

the awnser is c

Step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation