Acircle has an initial radius of 50 ft when the radius begins decreasing at the rate of 5 5 ft/min. what is the rate in the change of area at the instant that the radius is 26 26 ft?

  -816.8 ft²/min

Step-by-step explanation:

The rate of change of area is the product of the rate of change of radius and the circumference of the circle. At the time of interest, ...

  dA/dt = C·dr/dt = 2πr·dr/dt

  dA/dt = 2π·(26 ft)(-5 ft/min)

  dA/dt = -260π ft²/min ≈ -816.8 ft²/min

google dat sis

step-by-step explanation:

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