Marcus ran to the park and then walked to the store. he ran 3 times as long as he walked. the total time spent walking and running was 24 minutes. what equation is used to solve for how long it took marcus to walk from the park to the store?

time (t) = distance (d) / speed (s)

total time (t) = time riding (t1) + time walking (t2)

1 hour = [6 miles / s1] + [1 mile / (s1 - 6 mph)]

multiply both sides by s1(s1-6)

s1(s1-6)=6(s1-6)+s1

s1^2-6s1 = 6s1-36+s1

s1^2-13s1+36=0

(s1-9)(s1-4)=0

two possible solutions s1 = 9 mph or s1 = 4 mph

since s2 = s1 - 6, then s2 = 9-6 = 3 mph (accept) or s2 = 4-6 = -2 mph (reject)

then riding speed = 9 mph and walking speed = 3 mph

Step-by-step explanation:

time (t) = distance (d) / speed (s)

total time (t) = time riding (t1) + time walking (t2)

1 hour = [6 miles / s1] + [1 mile / (s1 - 6 mph)]

multiply both sides by s1(s1-6)

s1(s1-6)=6(s1-6)+s1

s1^2-6s1 = 6s1-36+s1

s1^2-13s1+36=0

(s1-9)(s1-4)=0

two possible solutions s1 = 9 mph or s1 = 4 mph

since s2 = s1 - 6, then s2 = 9-6 = 3 mph (accept) or s2 = 4-6 = -2 mph (reject)

then riding speed = 9 mph and walking speed = 3 mph

Step-by-step explanation:

is this going to help

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

i belive those are the ones that are under 90 degreese.