The length of a rectangular picture frame is twice the width. the frame has a perimeter of 96 inches. write and
solve a system of equations to represent this solution. let x represent the width of the frame, and let y represent the
length of the frame. interpret the solution.

Length = 16 inches

Width = 32 inches

Step-by-step explanation:

Width of the frame is represented by x and length by y inches. It is given that length of the frame is twice the width. This means y is twice of x. So, we can write the equation as:

y = 2x                                      Equation 1

Perimeter of a rectangle is defined as:

Perimeter =  2 ( Length + Width )

Since, perimeter of the picture frame is equal to 96, we can write the equation as:

2(x + y) = 96                          Equation 2

Substituting the value of y from Equation 1 in Equation 2, we get:

2(x + 2x) = 96

2(3x) = 96

6x = 96

x = 16

Substituting the value of x in Equation 1, we get:

y = 2x = 2(16) = 32

This means, the length of the rectangular picture frame is 16 inches and its width is 32 inches.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: