Arocket was launched into the air from a podium 6 feet off the ground. the rocket path is represented by the equation h(t)=-16t^2+120t+6, where h(t) represents the height, in feet, and t is the time, in seconds. find the average rate of change from the initial launch to the maximum height.

60

Step-by-step explanation:

The given function is:

The average rate of change of h(t) from t=a to t=b is given by:

We can rewrite this function as:

The maximum height of the rocket is 231 and it occurs at t=3.75

The initial launch occurs at: t=0

and

The average rate of change from the initial launch to the maximum height is

4

step-by-step explanation:

47 - 90 = 43

43 - 180 = x

x = 137