If the distance covered by an object in time t is given by s(t)=2t^2+3t , where s(t) is in meters and t is in seconds, what is the average velocity over the interval from 2 seconds to 4 seconds?
answers:
a) 15m/s
b) 14m/s
c) 13m/s
d) 12m/s
e) 11m/s

a) 15 m/s.

Step-by-step explanation:

s(t) = 2t^2+ 3t

Distance at 2 seconds =  s(2) = 2(2)^2 + 3(2) =  14 m.

Distance at 4 seconds =  s(4) = 2(4)^2 + 3(4) =  44 m.

Average velocity = distance travelled from t = 2 until t = 4 /  time

= (44 - 14) / 4 -2

= 30/2

= 15 m / s.

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.