In one town, 66% of adults have health insurance. what is the probability that 4 adults selected at random from the town all have health insurance? round to the nearest thousandth if necessary.

The probability that 4 adults selected at random from the town all have health insurance is 0.1897

Step-by-step explanation:

Consider the provided information.

It is given that 66% of adults have health insurance.

Let p = 66% = 0.66

Therefore q=1-0.66=0.34

We need to find the probability that 4 adults selected at random from the town all have health insurance.

Here the value of r is 4.

Substitute the respective values in the above formula.

Hence, the probability that 4 adults selected at random from the town all have health insurance is 0.1897

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.