Correct answers only !
use the following information to find your course average in amdm, if homework is weighted 20%, class participation is 25%, test grades are 30%, and final exam is 25%.
 homework {90, 94, 96, 90}
 class participation {95, 99}
 test grades {87, 75, 82 ,85}
final exam grade {71}
18.5 + 24.25 + 24.675 + 17.75
a. 85
b. 88.5
c. 87
d. 89

First question : A. 85,

Second question : 71%

Step-by-step explanation:

First question :

Percentage marks in home work,

90, 94, 96, 90,

So, the average percentage marks in home work = = 92.5

∵ Weightage in home work = 20%,

So, the weightage marks in home work = 20% of 92.5 = 0.20(92.5) = 18.5

Similarly, the class participation is weighted 25%,

So, the weightage marks in class participation

= 24.25

The test grade weighting 30%,

So, the weightage marks in class participation

= 24.675

The final exam weightage is 25%,

So, the weightage marks in final exam,

= 17.75

Hence, the total average = 18.5 + 24.25 + 24.675 + 17.75  ≈ 85

Second question :

Given,

Averages of Mark in his AMDM maths class,

Homework : 95,

Quiz average : 80,

Test average : 67,

Final average : 60,

Also, the weightage,

In home work is 10%,

In Quiz test is 20%

In test is 50%

In final exam is  20%

Hence, Marks class average =

= 71 %

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15