What is the product?
(-3s+2t)(4s-t)

12s² + 11st - 2t²

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

- 3s(4s - t) + 2t(4s - t) ← distribute both parenthesis

= - 12s³ + 3st + 8st - 2t² ← collect like terms

= - 12s² + 11st - 2t²

-12s²+11st-2t²

Step-by-step explanation:

(-3s+2t)(4s-t)

=−3s(4s)  −3s(−t)+2t(4s)+2t(−t)

=-12s²+3st+8st-2t²

=-12s²+11st-2t²

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!