Find the midpoint of diagonal ac of abcd

M= (1, 3)

Step-by-step explanation:

we have from the picture:

A = (-3,5)

C = (5, 1)

M = Midpoint

M =((x1+x2)/2), ((y1+y2)/2)

so we have:

x1= -3     y1 = 5

x2= 5     y2= 1

M= ((-3+5)/2) , ((5+1)/2)

M = ((2/2) , (6/2))

M= (1, 3)

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

pls mark as brainliest

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4