Core: 0 of 1 pt
1.7.43
find (a) pq to the nearest tenth and (b) the coordinates of the midpoint of pq.
p(1,2), q(4, -3)
(a) pq = 5.8 (round to the nearest tenth as needed.)
(b) the coordinates of the midpoint of pq are
(type an ordered pair.)

d) the triangle is a right triangle 60 squared +144 squared= 156 squared

step-by-step explanation:

156 squared is the hypothenuse

so 156= c

i cant see the graph

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl