Someone me on geometric problem. equations practice.

AOB = 36°

Step-by-step explanation:

Because we know that OA is perpendicular with OC so AOC would = 90°

So AOB + BOC = AOC

(6x - 12) + (3x + 30) = 90

6x - 12 + 3x + 30 = 90

6x + 3x + 30 - 12 = 90

9x + 18 = 90

9x = 90-18

9x = 72

x = 8

So to find AOB, we would apply it to the equation:

AOB = 6x - 12

= 48 - 12

= 36°

Hope this helped :3

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: