Mozp=4r+2,m pzq=5r-12, and m ozq=125. what are m ozp and m pzq

 ∠OZP = 62     ∠PZQ = 63

Step-by-step explanation:

Use the Angle Addition Postulate

∠OZP  +  ∠PZQ  =  ∠OZQ

(4r + 2) + (5r - 12) = 125

                9r - 10 = 125

                9r        = 135

                         r = 15

∠OZP = 4r + 2

          = 4(15) + 2

          =  60 + 2

          =   62

∠PZQ = 5r - 12

          = 5(15) - 12

          =  75 - 12

          =  63

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation: