*20 points*
what value of c makes x2 + 6x + c a perfect square trinomial?
c =
if x2 + 6x + c = (x + d)2, then d =

c=9

d=3

Step-by-step explanation:

We have been asked:

What value of c makes x2 + 6x + c a perfect square trinomial?

c =  

If x2 + 6x + c = (x + d)2, then d =

First step we have to do is divide the coefficient of x by 2. The coefficient is 6

6/2 = 3

Now take the square of 3 = 3^2

3^2 = 3*3 =9

The value of c is 9

If x^2 + 6x + c = (x + d)^2, then d =?

Put the value of c in the equation:

x^2+6x+9

Take the square root of 1st and third term. Then the expression can be written as:

x^2+6x+9 = (x+3)^2

Thus the value of d is 3.

If x^2 + 6x + 9 = (x + 3)^2, then d = 3

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: