Suppose germination periods, in days, for grass seed are normally distributed and have a known population standard deviation of 6 days and an unknown population mean. a random sample of 21 types of grass seed is taken and gives a sample mean of 34 days. find the margin of error for the confidence interval for the population mean with a 99% confidence level.

3.725

Step-by-step explanation:

Formula of Margin of Error for (n<30):-

Given : Sample size : n= 21

Level of confidence = 0.99

Significance level :

By using the t-distribution table ,

Critical value :

Standard deviation:

Then, we have

Hence, the margin of error for the confidence interval for the population mean with a 99% confidence level=3.725

two data sets with the same median will not have the same varaibility

step-by-step explanation:

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier