Company b: starting salary-28,000 yearly salary increase-2,400
company c: starting salary- 36,000 yearly salary increases- 2,000
question: paul started at company b 10 years ago at the salary shown in the table. at the same time, sharla started company c at the salary shown in the table. who earned more durning the 10th year? how much more?
in the last year, earned $ more.

Sharla, 4400

Step-by-step explanation:

Paul's Salary:

Paul started at company B. Starting salary of company B is $ 28,000 with a yearly increase of $ 2,400. Paul's Salary in first year will be 28,000. In second year his salary will be 28000 + 2400, in 3rd year his salary will be: 28000 + 2(2400) and so on.

Since, the increase in Paul's salary every year is $ 2400, the increase in his salary after 10 years or in 10th year would be = 2400 x 9 = $ 21,600

So, his total salary in 10th year would be = 28000 + 21600 = $ 49,600

Sharla's Salary:

Sharla started at company C. Starting salary of company C is $ 36,000 with a yearly increase of $ 2,000.

Since, the increase in Sharla's salary every year is $ 2000, the increase in her salary after 10 years or in 10th year would be = 2000 x 9 = $ 18,000

So, her total salary in 10th year would be = 36000 + 18000 = $ 54,000

Conclusion:

Sharla earned more in 10th year an amount equal to $ 4400. So the answer is:

In the last year, Sharla earned $4,400 more.

d. it is a convex pentagon because it has five sides and none of the sides would extend into the inside of the polygon.

step-by-step explanation:

50x5=$250

step-by-step explanation: