Mathematics, 27.08.2019 06:30 mdlnlcs

Using predicate logic, prove the argument
(∀x)[p(x)^q(x)] → (∀x)p(x)^(∀x)q(x)

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Using predicate logic, prove the argument
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Using predicate logic, prove the argument(∀x)[p(x)^q(x)] → (∀x)p(x)^(∀x)q(x)

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Using predicate logic, prove the argument
(∀x)[p(x)^q(x)] → (∀x)p(x)^(∀x)q(x)