Two consecutive odd number are such that three times the first is 5 more than twice the second. what are those two odd numbers?

The first consecutive odd number is: 9

and the second consecutive odd number is: 11

Let the two consecutive odd numbers be: a and a+2

( Since, we know that the difference between two consecutive odd or two consecutive even numbers is always 2 )

Now, it is given that:

Three times the first is 5 more than twice the second.

i.e.

Hence, we get:

The first consecutive odd number is: 9

and the  second consecutive odd number is: 9+2=11

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant

answer: h=5.6 i don't really know how to put into words, so i though i would let you do that. i hope i was able to some

step-by-step explanation:

18 = 6(h)+1/2

18 = 6h+1/2

18-1 = 6h/2

17 = 3h

17/3 = h

h = 5.6