The sum of five consecutive integers is equal to the sum of the next three consecutive integers. what is the largest of these eight integers

let n be the first integer. then the next five integers are n+1, n+2..n+4. the next three are n+5..n+7. so:

n+n+1+n+2+n+3+n+4=n+5+n+6+n+7

5n+10=3n+18

2n=8

n=4

the largest number is n+7, or 11.

step-by-step explanation:

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