The lp relationships that follow were formulated by richard martin at the long beach chemical company. maximize 8x1 + 0.5x1 x2 + 5x3subject to: 1x1 x2 + 2x3 ≤ 70 (c1)10.9x1 - 4x2 ≥ 156 (c2)5x1 + 3x2 + 3x3 ≥ 21 (c3)16x2 - 0.33x3 = 17 (c4)-7x1 - x2 + 4x3 = 5 (c5)1x1 + 2x2 + 3squareroot of x3 ≤ 80 (c6)for an lp, the objective function developed by richard is valid or invalidconstraint c1 is(n) valid or invalidconstraint c2 is(n) valid or invalidconstraint c3 is a(n) valid or invalidconstraint c4 is a(n) valid or invalidconstraint c5 is a(n) valid or invalidconstraint c6 is a(n) valid or invalid

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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explanation:

step-by-step explanation:

can i know which language is this?